Nitrobenzene on reduction with Zn and NH4Cl gives
(A) aniline
(B) nitrosobenzene
(C) phenylhydroxylamine
(D) hydrazobenzene
Correct Answer: (C) phenylhydroxylamine
Summary of options:
- (A) Aniline – requires strong reduction (e.g., Sn/HCl).
- (B) Nitrosobenzene – formed under even milder conditions.
- ✅ (C) Phenylhydroxylamine – correct.
- (D) Hydrazobenzene – formed from reduction of nitrobenzene in basic medium (Zn/NaOH).

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