Nitrobenzene on reduction with Zn and NH4Cl gives
(A) aniline
(B) nitrosobenzene
(C) phenylhydroxylamine
(D) hydrazobenzene

Correct Answer: (C) phenylhydroxylamine

Summary of options:

  • (A) Aniline – requires strong reduction (e.g., Sn/HCl).
  • (B) Nitrosobenzene – formed under even milder conditions.
  • ✅ (C) Phenylhydroxylamine – correct.
  • (D) Hydrazobenzene – formed from reduction of nitrobenzene in basic medium (Zn/NaOH).

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