Which of the following alkanes cannot be prepared by Wurtz reaction?
(A) Methane
(B) Ethane
(C) Propane
(D) 2-Methylpropane
(A) Methane:
- Would require coupling of methyl halide (CH₃–X) with itself.
- This gives ethane (CH₃–CH₃), not methane.
- So methane cannot be prepared by Wurtz reaction.
(B) Ethane:
- Formed by coupling of two methyl halide molecules (CH₃–X).
- Ethane can be prepared.
(C) Propane:
- Would require coupling of methyl halide (CH₃–X) and ethyl halide (C₂H₅–X).
- This is unsymmetrical, and Wurtz reaction gives a mixture (ethane, propane, butane).
- Propane cannot be prepared cleanly.
(D) 2-Methylpropane (isobutane):
- Can be obtained by coupling of isopropyl halide (CH₃–CHBr–CH₃) and methyl halide.
- Again, leads to mixtures — not ideal.
- Cannot be prepared selectively.
Final Correct Answer:
(A) Methane — it cannot be prepared by the Wurtz reaction.

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